Question

a projectile of mass 50kg is shot vertically upward with an initial velicity of 100m/s .after 5 sec it explodes into two fragments one of which having mass 20kg travel vertically up with a velocity of 150m/s .what us the velocity of the other fragment at that instant​

Answer 1

Answer:

the velocity of the other fragment at that instant​ = 50/3 m/s Downward

Explanation:

A projectile of mass 50kg is shot vertically upward with an initial velocity of 100m/s

Initial Velocity = 100 m/s

a = g = -10m /s

Velocity after 5 sec = 100 +(-10)*5 = 50 m/s

mass = 50 kg

Momentum = mv = 50 * 50

mv = m1v1 + m2v2

50 * 50  = 20 * 150  + (50-20)v

=> 2500 = 3000 + 30v

=> 30v = -500

=> v = -50/3

the velocity of the other fragment at that instant​ = 50/3 m/s Downward

Answer 2

Explanation:

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