Question

A projectile of mass m is fired with velocity v at angle theta with horizontal what is the change in momentum as it rises to the highest point of trajectory

Answer 1

Answer:

p=mv mass of the object will not change At the highest point Vy is 0 and Vx will be equal to Ux of the ball as there is no acceleration acting in x direction. So Ux=v cos theta So momentum at the highest point=m(v cos theta) Initial momentum=mv So change in momentum=mv- m(v cos theta)= mv(1- cos theta) I hope your doubt is clear now..

Explanation:

i hope it's very easy for you