A projectile of mass m is projected with velocity v at an angle theta with horizontal. if the time of projectile is t then the magnitude
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on reaching the plane again ..y becomes zero
i.e y=0
so we will find the time taken in doing so
on putting y=0 in displacement time eqn we get ...
t=2vsin theta/g
i.e y=0
so we will find the time taken in doing so
on putting y=0 in displacement time eqn we get ...
t=2vsin theta/g
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