Question

A projectile of mass m is thrown with speed u at an angle theta from the horizontal. The moment of the gravitational force on the projectile about point of projection,t time after the projection,is​

Answer 1

Answer:

the moment of the gravitational force on the projectile abouy point of projection force on the projectile about point of projection.

Answer 2

Answer:

M = mg .  u cosθ

Explanation:

Given that

Mass= m

Speed = u

As we know that in projectile motion acceleration is only in vertical direction,so the force only will be in vertical direction.

The vertical force F= m g

We also know that the horizontal component of velocity u is constant in projectile motion.

Horizontal component of u = u cosθ

So the horizontal distance after time t

x =  u cosθ

We know that moment M

M = F .d             ( d is the perpendicular distance to the force)

M= mg .x

M = mg .  u cosθ

So moment is ,M = mg .  u cosθ