Question

A projectile of mass m is thrown with speed u at an angle theta with horizontal.find it's angular momentum about point of projection? When particle is at highest point.

Answer 1

application of projectile motion

Answer 2

The angular momentum about the point of projection when the particle is at the highest point is (mu³ cos θ sin² θ)/2g

Explanation:

Angular momentum = Linear momentum × Perpendicular from the fixed point

Where,

Linear momentum = mvr = mu cos θ

Perpendicular from the fixed point = Maximum height of the projectile

The maximum height is given by the formula:

H = (u² sin² θ)/2g

Now, the angular momentum is:

L = (mu cos θ) × (u² sin² θ)/2g

∴ L = (mu³ cos θ sin² θ)/2g