Question

A projectile of mass m is thrown with the speed u at an angle theta from horizontal. The moment of the gravitational force on the projectile about point of projection t time after the projection is​

Answer 1

Answer:

Explanation:

Mass of the Projectile = m (Given)

The force of the horizontal distance marked = W

Torque = Range × Force

The Magnitude Of Torque = Force × Range SinФ

Magnitude of Torque = F.r.SinФ

Since, Force = Mass × Gravity = F = mg

Substituting in the formula -

Torque = mg * r / 2

where r will be - r = [ u² . sin 2 Ф / g ]

Thus,

Torque = mg / 2 × [ u² 2 sin Ф. cos Ф / g ]

Torque = m [ u² sin Ф . cos Ф ]

Torque = Mass × Speed² Sin Ф . Cos Ф

T = MU² Sin Ф. CosФ