Question

A projectile's launch speed is 2.50 times its speed at maximum height. Find the launch angle θ0.

Answer 1

Answer:

cos ^-1 2/5

Step-by-step explanation:

Let the launch speed be u and launch angle be x.

Velocity at maximum height is u cosx

u = 5/2 ucosx

cosx = 2/5

so, x = cos ^-1 2/5