A projectile takes off with an initial velocity of 10 m/s at an angle of elevation of 45°. It is just
able to clear two hurdles of height 2m each separated from each other by a distance d. Calculate
d. At what distance from the point of projection is the first hurdle placed? Take
g= 10 m/s2
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Answer:
Explanation:
We have,
u = 10m/s
h = 2 m
1) We know,
2)
Time taken to reach from max. Height to top of hurdle:
u_y = 0 (at Max height)
S_y = 2.5-2=0.5m
Using,
3) Now,
Time required to cross the hurdle from one to other is
Since, acceleration in horizontal direction is 0.
So,
4) Range of Projectile,
Then ,
Distance from point of projection to first hurdle placed is given by
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