Question

A projectile thrown with initial velocity
and its range is twice the maximum height attained by it, then
(A)
b = a/2
(B)
b= a
(C) b = 2a
(D) b = 4a
Mark For Review & Next
Clear Response

Answer 1

b = 2a

Explanation:

As we know,

R = 2H

$\frac{u^{2}sin2∅}{g}$ = 2 $\frac{u^{2} sin^{2}∅ }{2g}$

2sin∅.cos∅ = $sin^{2}$∅

tan ∅ = 2                   ... (equation 1)

The projectile velocity is calculated using,

v = ai + bj

tan ∅ = b/a          ...(equation 2)

By solving equation (1) and equation (2), we get

b/a = 2

so, b = 2a i.e. option C is the correct answer.

Learn more: initial velocity

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