Question

A projectile thrown with speed u=20m/s at an angle 30° with horizontal from the top of a building 40 m high.Then the horizontal range of projectile is

Answer 1

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Answer 2

Answer:

Explanation:

For a n object thrown from top of a height it's range is given by the formula...

R=u√2h/g.

Here an angle is also given with horizontal therefor the formula becomes

R=u√2h/g costheta

Therefor R=20√2×40/10.cos30

R=40√3