Question

a projectile will cover the maximum vertical distance in the minimum time when the angle of its projection is

Answer 1

Explanation:

it should be

$\frac{\pi}{2}$

because only in this case whole of the kinetic energy

$\frac{ 1}{2} m {v}^{2}$

is used to increase the height of the projectile. no kinetic energy is wasted in horizontal motion.

Answer 2

A projectile will cover the maximum vertical distance in the minimum time when the angle of its projection.

• We can see that for the longest-range punts 2 = 90 degrees and, consequently, = 45 degrees because the sine function has an input angle of 90 degrees that results in its highest output value, 1. In other words, a projectile moves the farthest when it is fired at a 45-degree angle.
• With no air resistance, a bullet can travel a maximum of 45 degrees.
• The beginning value of the vertical velocity component determines the peak height of a projectile. A projectile will rise higher the higher the initial value of vy is. The bullet fired at a 60-degree angle has the largest vy and, hence, the largest peak height.
• The beginning vertical velocity determines the height to the maximum. The maximum height increases as the launch angle is increased because steeper launch angles have a bigger vertical velocity component.

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