A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = –16t2 + 48t + 190.
What is the maximum height of the projectile?
82 feet
190 feet
226 feet
250 feet
Answers
Answered by
3
Answer:
the maximum is sent BNMNHGFEEFV
Step-by-step explanation:
Answered by
13
Answer:
c. 226
Step-by-step explanation:
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