Math, asked by awfultune, 3 months ago

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = –16t2 + 48t + 190.

What is the maximum height of the projectile?

82 feet
190 feet
226 feet
250 feet

Answers

Answered by jlyo0613
3

Answer:

the maximum is sent BNMNHGFEEFV

Step-by-step explanation:

Answered by tristaankawchaack
13

Answer:

c. 226

Step-by-step explanation:

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