A projectiles of mass m is fired with velocity v at an angle thitha with the horizontal what is the highest point of the trajectory? plsss vyus hlp me it's too urgent
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Answer: p=mv mass of the object will not change At the highest point Vy is 0 and Vx will be equal to Ux of the ball as there is no acceleration acting in x direction.
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Aap KV'ian ho ky....???
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