A property changed hands three times. Each broker who sold it charged 1% as brokerage. If each time it was sold for the net amount obtained at the previous sale, calculate its original sale value, if the third sale réalised 1,00,000 net.
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Answer:
we have given that
If the sale price of property = Rs. 300000
Rate of commission = 2%
Amount of commission is given by
\begin{gathered}\frac{2}{100}\times 300000\\\\=Rs. 6000\end{gathered}
100
2
×300000
=Rs.6000
Now, If the sale price of property = Rs. 450000
Rate of commission on remaining amount = 1.5%
So, Remaining amount is given by
\begin{gathered}450000-300000\\\\=150000\end{gathered}
450000−300000
=150000
Amount of commission will be
\begin{gathered}\frac{1.5}{100}\times 150000\\\\=Rs.2250\end{gathered}
100
1.5
×150000
=Rs.2250
So, Total broker's commission is given by
\begin{gathered}2250+6000\\\\=Rs. 8250\end{gathered}
2250+6000
=Rs.8250
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