a property dealer bought 10 acres of land at the rate of Rs 70000 per acre . He later subdivided the land into 22 plots and sold them at the rate of Rs 45000 per plot. Find his profit and profit percentage
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Cost price of 1 acre of land = Rs 70000
∴ Cost price of 10 acres of land = Rs 70000 × 10
= Rs 700000
Selling price of 1 plot = Rs 45000
∴ Selling price of 22 plot = Rs 45000 × 22
= Rs 990000
Plot of Property dealer = selling price of 22 plot – Cost price of 10 acres of land = Rs 990000 – Rs 700000 = Rs 290000
profit%= profit/cost price of 10acres of land
= 290000/700000*100
= 41.42 %
∴ Cost price of 10 acres of land = Rs 70000 × 10
= Rs 700000
Selling price of 1 plot = Rs 45000
∴ Selling price of 22 plot = Rs 45000 × 22
= Rs 990000
Plot of Property dealer = selling price of 22 plot – Cost price of 10 acres of land = Rs 990000 – Rs 700000 = Rs 290000
profit%= profit/cost price of 10acres of land
= 290000/700000*100
= 41.42 %
Answered by
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Answer:
Cost price of 1 acre of land = Rs 70000
∴ Cost price of 10 acres of land = Rs 70000 × 10
= Rs 700000
Selling price of 1 plot = Rs 45000
∴ Selling price of 22 plot = Rs 45000 × 22
= Rs 990000
Plot of Property dealer = selling price of 22 plot – Cost price of 10 acres of land = Rs 990000 – Rs 700000 = Rs 290000
profit%= profit/cost price of 10acres of land
= 290000/700000*100
= 41.42 %
Step-by-step explanation:
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