Math, asked by tejasppurohit, 11 months ago

A property dealer sells a house for Rs.
6,30,000 and in the bargain makes a
profit of 5%. Had he sold it for Rs.
5,00,000, then what percentage of
loss or gain he would have made?​

Answers

Answered by praneethks
11

Step-by-step explanation:

Let the original cost of the house be 100x. Profit% =5% so profit made on selling the house is 5/100 ×100x =>5x. Hence selling price of the house is 100x+5x=>105x= 630000 =>x=630000/105=6000. So the original cost of the house is 600000 ruppees. In the next case he sells it for 500000 ruppees. Loss made by him = Original Cost - Selling Price = 600000-500000 = 100000. Loss% = 100000/600000 × 100 => 100/6% =>16 2/3%

Hope it helps you.

Answered by ikrmohitkumawat
11

Answer:

SP= 6,30,000

Profit=5%

Then

CP= 100/105*630000

CP= 6,00,000

NOW

SP=100-X/100*CP

500000=100-X/100*600000

=16.66% loss

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