A proton, a deuteron and an alpha particle are accelerated through potentials of v , 2v and 4v respectively. Their velocities will bear a ratio
Answers
Answer:
velocity of proton= velocity of deuteron= (velocity of alpha particles)÷√2
Explanation:
The velocity and accelerating potentials are related by the formulas given below:
(1÷2)×m×v²= q×V
Where m =mass,
q=charge,
v= velocity,
V=accelerating potential.
The mass of alpha particle is 4 times the mass of proton and its charge is twice that of proton
velocity v1 of proton =√(q×V×2)÷m be equation 1
velocity v2 of alpha= √(2q×4V×2)÷4m be equation 2
From equation1 and equation 2 v2=√2×v1
Velocity of alpha particle is √2 times that of proton.
The mass of deuteron is twice that of proton and charge same as that of proton
velocity v3 of deutron= √(q×2V×2)÷2m let it be equation 3
From equation 1 and equation 3 v3= v1
Velocity of proton =velocity of deuteron
velocity of proton= velocity of deuteron= (velocity of alpha particles)÷√2