A proton and an alpha particle are projected with velocity
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A proton and an alpha-particle are projected with velocity v0 =(ke^2/ml)^1/2
each, when
they are far away from each other, as shown. The distance between their initial
velocities is L. Find their closest approach distance, mass of proton=m, charge=+e,
mass of a-particle = 4m, charge = + 2e.
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1
Answer:
Here is your answer
frequency,ν=qB/2πm where q ia charge and m is mass of the particle.
For proton ν
p=eB/2πm
and for alpha particle ν
a
=(2e)B/2π(4m)=ν
p/2
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