Question

a proton and an alpha particle enter a region of uniform electric field at right angles to the direction of the field with same velocity which particle describes greater circular path​

Answer 1

Explanation:

The radius of circular path is r=root 2mE

or, 1=EpEα as radius of both particles are equal and the mass of alpha particle is 4 times of proton and charge is 2 times of proton.

Thus, Eα=Ep=1MeV

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