Question

A proton and an alpha particle have the same kinetic energy in tge range of few ev. Find the ratio of de broglie wavelength associated with proton to that of alpha particle​

Answer 1

Answer:

Kinetic energy K = p^2/2m where m is the mass and p is the momentum. Thus, p = sqrt(2mK) = square root from 2mK. Wavelength = h/p = h/sqrt(2mK), where h is Planck's constant. The De Broglie wavelength of a particle is , thus the ratio .