Question

a proton and an alpha particle have their accelerating potential in the ratio 8:1. find the ratio of de-broglie wavelength ( step by step explaination ) if u dont know dont answer its urgent pls.​

Answer 1

Answer:

The relation between de Broglie wavelength λ and accelerating potential V is given by λ=

2mqV

h

So,

λ

α

λ

p

=

(

m

p

m

α

)(

q

p

q

α

)(

V

p

V

α

)

Here, λ

α

=λ

p

,

m

p

m

α

=4/1,

q

p

q

α

=2/1

Thus, 1=

(4)(2)

V

p

V

α

or

V

α

V

p

=

1

8

ii) Also , λ=

p

h

=

mv

h

Thus,

λ

α

λ

p

=

m

p

m

α

v

p

v

α

or 1=4

v

p

v

α

or

v

α

v

p

=

1

4

Answer 2

Answer:

Ratio= 2:1

Explanation:

V is given by λ=

2mqV

h

So,

λ

α

λ

p

=

(

m

p

m

α

)(

q

p

q

α

)(

V

p

V

α

)

Here, λ

α

=λ

p

,

m

p

m

α

=4/1,

q

p

q

α

=2/1

Thus, 1=

(4)(2)

V

p

V

α

or

V

α

V

p

=

1

8

ii) Also , λ=

p

h

=

mv

h

Thus,

λ

α

λ

p

=

m

p

m

α

v

p

v

α

or 1=4

v

p

v

α

or

v

α

v

p

=

1

4