a proton and an alpha particle have their accelerating potential in the ratio 8:1. find the ratio of de-broglie wavelength ( step by step explaination ) if u dont know dont answer its urgent pls.
Answers
Answered by
0
Answer:
The relation between de Broglie wavelength λ and accelerating potential V is given by λ=
2mqV
h
So,
λ
α
λ
p
=
(
m
p
m
α
)(
q
p
q
α
)(
V
p
V
α
)
Here, λ
α
=λ
p
,
m
p
m
α
=4/1,
q
p
q
α
=2/1
Thus, 1=
(4)(2)
V
p
V
α
or
V
α
V
p
=
1
8
ii) Also , λ=
p
h
=
mv
h
Thus,
λ
α
λ
p
=
m
p
m
α
v
p
v
α
or 1=4
v
p
v
α
or
v
α
v
p
=
1
4
Answered by
1
Answer:
Ratio= 2:1
Explanation:
V is given by λ=
2mqV
h
So,
λ
α
λ
p
=
(
m
p
m
α
)(
q
p
q
α
)(
V
p
V
α
)
Here, λ
α
=λ
p
,
m
p
m
α
=4/1,
q
p
q
α
=2/1
Thus, 1=
(4)(2)
V
p
V
α
or
V
α
V
p
=
1
8
ii) Also , λ=
p
h
=
mv
h
Thus,
λ
α
λ
p
=
m
p
m
α
v
p
v
α
or 1=4
v
p
v
α
or
v
α
v
p
=
1
4
Similar questions