a Proton and an electron are placed 1.6 CM apart in free space find the magnitude and nature of electrostatic force between them
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Since it is in free space, use the formula :
F= (1÷(4*pi*epsilon0)) ((q1*q2)÷r^2), where
q1=-q2= 1.6 ×10^-19 C , r= 1.6 m, and the value of
1÷(4*pi*epsilon0 ) is 9x10^9. Put these values into the equation that I have written and you will get your answer .
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