Question

a proton and an electron are seperated a distance of 1Angestron. then find electrostatic force between them​

Answer 1

Answer:

13.6eV

Explanation:

The electrostatic potential energy between proton and electron distance=

1A⁰ =1X$10^{-10}$ m

U= $\frac{1}{4πϵ _{0} }$ 4πϵ₀ $\frac{q₁q₂}{r}$ q₁q₂ (written so it is clear what is the denominator and numerator)

= $\frac{9X10^{9}X1.6X10^{-19}X1.6X10^{-19} }{10^{-10} }$

 =13.6eV

∵   (1eV =1.6×$10^{-19}$J)