A proton and an α-particle are accelerated through the same potential difference. The ratio of their De Broglie wavelength is ??
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proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-particle is.
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We know, λ =h / √2mqv
Since protons and α particles are accelerated through same potential .V is same.
λ p / λ α = (√2(4m)(2q)V) / (2(4m)(2q)V) = 8
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