A proton and fallow same circular path in magnetic field the ratio of kineyic energies
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radius described by charged particle in magnetic field is given by, or,
where P is linear momentum of charged particle, q is charge on it and B is magnitude of magnetic field .
we know, kinetic energy , K = P²/2m
so, P = √{2Km}
now r = √{2Km}/qB
if K and B are constant then, r is directly proportional to square root of m and inversely proportional to q.
or,
mass of proton,
mass of alpha particle,
charge on proton,
charge on alpha particle,
so, ratio of radius = √(1u/4u) × (2e/1e) = 1
hence, ratio of radius described by them is 1 : 1
hope it helps u
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