Question

A proton and photon have.Same de broglie wavelength prove that energy of photon...Is 2mc/h times k. E

Answer 1

Therefore, KE of the photon (which is also the total energy of the photon) is greater than the kinetic energy of the electron, both having the same wavelength. It then gives the expression p = h / λ. ... The Wikipedia article gives the expression λ = h / mc which is similar to the de Broglie expression.