Question

a proton carrying 1MeV kinetic energy is moving in a circular path or radius r in uniform magnetic field . what should be the energy of alpha particle to describe a circle of same radius in the field​

Answer 1

Answer:

For a particle of mass m and charge Q in a magnetic field, the radius of the path is given by;

r= $\sqrt{x}$2m(KE)/qB

q∝ $\sqrt{x}$m(KE)

2e/e=$\sqrt{x}$(mp)(IMeV)/(4m p)(KE)

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1/4= 1/4(KE)

KE=1MeV

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