Question

a Proton enters a magnetic field of 1500 Newton per ampere metre with the velocity of 2 into 10 to the power 6 metre per second find the force exerted on the proton if it and the perpendicular to the field parallel to the field make an angle of 30 degree with the field charge of a Proton equal to 1.6 into 10 to the power minus 19 ccoulomb

Answer 1

Explanation:

Force=4.8×10^(-10)Newton