Question

a proton enters a magnetic field of 4T INTENSITY with a velocity of 2.5 × 10 power 6 ms power -1 at an angle of 30degree with the field . find the magnitude of the force on proton. charge on the proton = 1.602 × 10 power -19 C . PLZZ ANS THIS QUEZ PLZZ WANNA AM CRYING PLZZZZZ

Answer 1

$Question:$

A proton enters a magnetic field of 4 T intensity with a velocity of 2.5 × 10⁶ ms⁻¹ an angle of 30° with the field. Find the magnitude of the force on the proton . Charge on the proton = 1.602 × 10⁻¹⁹ C.

$Solution:$

Given :

• B = 4 T
• v = 2.5 × 10⁶ ms⁻¹.

We know that ,

F = q v B Sin ∅

  = 1.6 × 10⁻¹⁹ × 2.5 × 10⁶ × 4 × $\frac{1}{2}$

 

simply it we get,

F = 8 × 10⁻¹³ N.

Thanks....