Question

A proton enters a region of uniform electric field Ē of strength 10 N/C with velocity 106 m/s, perpendicular to the electric field. The displacement of the proton when it covers a distance of 2.0 cm will be (mp = 1.67x10-27 kg, qp = 1.6x10-19 ) 1. 19.2 mm 2. 1.92 mm 3. 0.192 mm 4. 0.0192 mm​

Answer 1

Answer:

A proton enters a region of uniform electric field Ē of strength 10 N/C with velocity 106 m/s, perpendicular to the electric field. The displacement of the proton when it covers a distance of 2.0 cm will be (mp = 1.67x10-27 kg, qp = 1.6x10-19 ) 1. 19.2 mm 2. 1.92 mm 3. 0.192 mm 4. 0.0192 mm