A proton falls through a distance 3.5 cm in a uniform electric field of magnitude 2×10^4 NC^-1 . The acceleration of the proton is__________ ms^-2 ( Mass of the proton is 1.6 × 10^-27 kg )
Answers
ATQ, S=1.5cm=1.5×10
−2
m
u=0m/s
m
e
: mass of electron =9.10×10
−31
Kg
m
p
: mass of proton =1.672×10
−27
Kg
from coloumb's force,
F
=q
E
and given
E
=2×10
4
N/c
force proton
F
(+)
=1.6×10
−19
×2×10
4
=3.2×10
−19
N
force on electron,
F
(−)
=−1.6×10
−19
×2×10
4
=−3.2×10
−15
N
From Newton's Second law,
F
=m
a
for proton, a
(+)
=
m
p
F
(+)
=1.913×10
12
m/s
2
for electron, a
(−)
=
m
e
F
(−)
=−0.35×10
16
m/s
2
from equ of motion, S=ut+
2
1
at
2
⟶(1)
ATQ, The direction of the field was reversed, hence we will ignore the sign convention for acceleration.
∴ Substituting values in equ (1) for proton,
1.5×10
−2
=
2
1
×1.913×10
12
×t
2
1.568×10
−14
=t
2
⇒t=1.252×10
−7
seconds
Substituting values in equ(1) for electron,
1.5×10
−2
=
2
1
×3.5×10
15
×t
2
0.857×10
−17
=t
2
⇒t
0
=2.927×10
−19
seconds
Given data : A proton falls through a distance 3.5 cm in a uniform electric field of magnitude 2 * 10⁴ N/C.
To find : The acceleration of the proton ?
Solution : A/C to question;
- Electric field, E = 2 * 10⁴ N/C
- Charge on the proton, q = 1.602×10^(-19) C
- Mass of the proton, m = 1.6 * 10^(-27) kg
Here, we know downward electric field causes the proton to collapse/fall and A proton falls through a distance 3.5 cm {3.5 * 10^(-2)m} in uniform electric field.
Now,
➜ Force = mass * acceleration
➜ F = m * a
Here,
➜ Electric field of a point charge : E = F/q
∴ F = E * q
Hence,
➜ E * q = m * a
Now,
➜ E * q = m * a
➜ 2 * 10⁴ * 1.602×10^(-19) = 1.6 * 10^(-27) * a
➜ 3.204 * 10^(-15) = 1.6 * 10^(-27) * a
➜ a = 3.204 * 10^(-15)/1.6 * 10^(-27)
➜ a = 2.0025 * 10¹² m/s²
Answer : A proton falls through a distance 3.5 cm in a uniform electric field of magnitude 2 * 10⁴ N/C . The acceleration of the proton is 2.0025 * 10¹² m/s². {Mass of the proton is 1.6 × 10^(-27) kg}.
{More info :
- Protons are positively charged particles.
- They have a mass of 1.67×10^(-27)kg .
- They are present inside the nucleus.
- Proton is said to be very stable whether it's in its free state or inside the atoms. They do not decay spontaneously.
- The atomic number of an element is equal to the number of protons in the atom.
- Protons are represented as p+}