A proton has a mass 1.67*10^(-27) kg and charge +
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The kinetic energy is 1.6 x 10^-14 J
Explanation:
A proton had a mass of 1.67 ?10^-27 kg and charge +1.6 ?10^-19C. If the proton is accelerated through a potential difference if a million volts, then the kinetic energy is?
Initially the proton is at rest so kinetic enerfy is zero
Total energy = Kinetic energy + Potential energy
Thus the potential energy at rest moment.
- Potential energy = q x v
= 1.6 x 10^-19 C x 1 x 10^6 V
When the proton is accelerated it has gained Kinetic energy.
T.E = K.E + PE
- Kinetic Energy = 1/2 mv^2
- As both are equal so
K.E = qv = 1.6 x 10^-19 C x 1 x 10^6 V = 1.6 x 10^-13 J
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A proton had a mass of 1.67 ?10^-27 kg and charge +1.6 ?10^-19C. If the proton is accelerated through a potential difference if a million volts, then the kinetic energy is?
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