Question

A proton is accelerated through a potential difference DV. The change in kinetic energy of the particle will be
AV
2eAV
eV
2
Zero​

Answer 1

Given:

Proton is accelerated through a potential difference of V.

To find:

Change in Kinetic Energy of the proton.

Calculation:

Change in kinetic energy of the proton is equal to the change in potential energy of the proton.

Again, change in potential energy will be equal to the product of charge and potential difference.

$\therefore$ ∆KE = ∆PE

=> K - 0 = (Charge) × ∆V

=> K = e × V

=> K = eV.

So, final answer is

$\boxed{ \sf{ \large{K_{final} = eV}}}$