A proton is accelerated through a potential difference of 900v.its de-Broglie wavelength is a. 0.2 nm b.0.3nm c.0.8nm d. 0.4nm
Answers
Answered by
1
Answer:
b.0.3nm mark me as brainliest
Answered by
0
Answer:
b. 0.3
Explanation:
thanks for point....
Similar questions