Question

A proton is moving with a velocity 7×10 power 6 m/s towards right and neutron mass nearly equal to that proton is moving with velocity 4×10 power 6m/s towards left they collide and a duetron is formed the duetron will move with a velocity

Answer 1

Explanation:

Given,

mass=1.67×1027kg, Velocty of proton is 7.0×106m/s  Velocity of neutron is 4.0×106m/s

So, BY the conservation of momentum, let m be the mass of the proton, so 2m is the mass of the deuteron.

Initially, the momentum of the proton is −m×7×106kgm/s

Initial momentum of the neutron is +m×4×106kgm/s

so, total momentum is −m×106kgm/s

Now, after the attachment of the mass 2m,

Let v be the velocity of the deuteron,

Then 2mv=−m×3×106

Canceling m then e get,

v=−1.5×106m/s

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