Chemistry, asked by hardik2005kumar, 9 months ago

A proton is moving with kinetic energy 5 X 10^(-27) J. What is the velocity of the proton?

PLEASE ANSWER

Answers

Answered by vineet9900

9

Explanation:

we know K.E =1/2mV^2

V^2= 2K.E/m

V^2= 2x5x10^-27

V=√10x10^-28 velocity

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