Question

A proton moves along the x axis according to the equation T=√x-50t/10.where x is in meter and t is in second.calculate the average velocity of the proton in first 3.0s of its motion

Answer 1

Given: A proton moves along the x axis according to the equation T=√x-50t/10 where x is in meter and t is in second

To find: The average velocity of the proton in first 3 s of its motion.

Solution:

• Now we have given the equation as:

                  t = √( x - 50t ) / 10

• Now solving this, we get:

                  10t = √( x - 50t )

• Squaring on both sides, we get:

                  100t^2 = x - 50t

                  100t^2 + 50t = x

• Now let t = 3 seconds, then :

                  x = 100(3)^2 + 50(3)

                  x = 100(9) + 150

                  x = 900 + 150

                  x = 1050

• Now we know that:

                  average velocity = total displacement / total time

• Putting the values in it, we get:

                  average velocity = 1050 / 3 = 350 m/s

Answer:

          So the average velocity is 350 m/s.

Answer 2

Answer:Given: A proton moves along the x-axis according to the equation T=√x-50t/10 where x is in meter and t is in second

To find The average velocity of the proton in the first 3 s of its motion.

Solution:

Now we have given the equation as:

t = √( x - 50t ) / 10

Squaring on both sides, we get:

10t^2 = x - 50t

10t^2 + 50t = x

Now let t = 3 seconds, then :

x = 10(3)^2 + 50(3)

x = 10(9) + 150

x = 90+ 150

x = 240

Now we know that:

average velocity = total displacement / total time

Putting the values in it, we get:

average velocity = 240/3 = 80 m/s

Answer:

So the average velocity is 80 m/s.

HOPE IT IS HELPFUL :)