Question

A proton moves at a speed of 7.9×103 m/s as it passes through and is perpendicular to a 0.45-T uniform magnetic field. Find the radius of the circular path. 1. 5.6×10-7 m 2. 1.8×10-4 m 3. 1.0×10-4 m/s 4. 3.4×10-3 m

Answer 1

Answer:

apply this

F = q v B ( loreng force ) = mv2/r ( centripetal force )

so

r= mv2/ qV B apply this formula u will get answers

reason = as charged particles move perpendicular to magnitic field it move on circle .

hope u understand pleasark as brain list answer

Answer 2

SOLUTION-;

• he radius is given by r=  
• eB
• mv
• ​  
• ⇒  
• m
• e
• ​  
• =  
• rB
• v
• ​  
•