Question

) A proton moves in the x-y plane with a
speed of 2x106 ms-1. Its direction of
motion makes an angle of (a)0°, (b) 45° (c)
600 and (d) 90° with y-axis. There is a
magnetic field of 1mt directed along the
positive y - axis. Calculate the magnetic
force on the electron in each case [charge
of proton = 1.6x10-19 C]​

Answer 1

Answer:

import entitymanager.Entity; //import 'Entity' class

import entitymanager.EntityException; //import 'EntityException' class

public class Example {

public static void main(String[] args) {

try{

Entity entity = new Entity(); //create an object of 'Entity' class

System.out.println("user : "+entity.getEntity("username")); //prints 'sybero'

System.out.println("pass : "+entity.getEntity("password")); //prints '123@sybero'

System.out.println("host : "+entity.getEntity("hostname")); //prints 'host.sybero'

}catch(EntityException e){

System.out.println(e.getMessage());

}

}

}