Question

A proton moving at a speed of 5 kilometre per second makes an elastic collision with an other proton initially at rest .given that after collision the moving proton moves at an angle 37 degree with speed v1 and proton at rest moves at angle of theta2 in downward direction with x axis with speed v-2 to find v1 ,v2 and theta 2​

Answer 1

Explanation:

A proton moving with a velocity of 1.25×10

5

m / s collides with a stationary helium atom. The velocity of proton after collision is

MEDIUM

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ANSWER

Using momentum conservation,

mv=4mv

2

+mv

1

e=

v

v

2

−v

1

=1

v

2

−v

1

=v

4v

2

+v

1

=v

v

2

=

5

2

v

v

1

=

5

−3

v

=

5

−3

×1.25×10

5

=−7.5×10

5

m/s