A proton moving horizontally with a constant velocity enters uniform electric field acting in vertical direction which exerts a force of 2 x 10-25 N on the proton. Calculate the vertical acceleration of the proton inside the field if mass of proton is 1.66 x 10-27 kg. (Hint. F = qE)
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Answer:
formula
- F= ma
- a=2x10^-25\166X10^-27X100
- a-12*10^-3
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