Question

a proton moving with a speed of 5 into 10 raise to 6 metre per second is subjected to a magnetic field of 0.4 Tesla in blind at 30° to the direction of velocity of the proton what is the acceleration of proton mass of proton is 1.6 into 10 raise to minus 27 kg

Answer 1

F=B*q*v*sin(theta)

where B=magnetic field=0.4T

q=charge of proton=1.6*10^(-27)c

v=velocity of proton=5*10^6m/s

theta=angle=30°

now, m*a=0.4*1.6*5*10^(6-27)*sin30

a=(3.2*10^(-21)*1/2)/1.6*10^(-27)

a=10^6 m/s^2