a proton of mass charge e is released from rest in a uniform electric felid of strength E . the time taken by it to tral a distance d in the feild is
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We know that, electric field intensity is;
- E = F/q
- Eq = F - - - - - - - (i)
- { where E = electric field intensity, q = charge and F = Force }
Also, force is directly proportional to mass and accleration;
- F = ma
- Eq = ma - - - - - - - { from eq(i) }
- Eq/m = a
From question we have, the proton is released from rest and thus;
- Initial velocity(u) = 0
According to 2nd equation of motion:
- S = ut + ½at² - - - - - - - { put s = d, acc. to ques)
- d = 0t + ½ × Eq/m × t²
- d = ½ × Eq/m × t²
- 2d = Eq/m × t²
- 2md/Eq = t²
- √2md/Eq = t
Therefore, the total time taken will be √2md/Eq.
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