Physics, asked by zara0, 1 year ago

A proton passes through magnetic field with velocity 2.0×105m/s Perpendicularly. If the force acting on proton is 3.2×10-10N,find intensity of magnetic field.

Answers

Answered by ANMOL9654

3

Answer:

force = qvbsintheta

sintheta is 1

force = qvb

magnitude of magnetic field is 10 raise to the power 4

Explanation:

Answered by tech09shukla

6

Answer:

hey mate...

Explanation:

your answer is...

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