Physics, asked by AswathyPanickar, 11 months ago

A proton placed in an electric field would experience an electrical force equal to its weight. What will be the magnitude of electric field intensity E?

Answers

Answered by kingrahib

1

Answer:

Explanation:as we know F=qE

F=weight of proton=9.8×1.67×10^-27

q=1.6×10^-19

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