A proton released from rest in a region of a uniform electric field undergoes a displacement through a potential difference of -300 V. The change in its kinetic energy (in eV) is
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Explanation:
Since the field is uniform, the potential difference will be given by the product of the electric field and the distance. so it will be 8×0.5×10
4
=4×10
4
VChange in potential energy will be the work done by the proton.
That will be charge×PD
We know that one proton charge is 1.6×10
−19
C
Hence the answer is −6.4×10
−15
J
The negative sign shows that the PE decreases as the proton does work.
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