Physics, asked by dipendra08441, 3 months ago

A proton with the rest mass of 1.67 x 10-24 kg is initially moving at 0.90c in the +x-direction,
relative to the reference frame of a physics laboratory. Then a constant force
F = (-3.0 x 10-12 N) î+ (5.0 x 10-12 N) i
is applied to the proton. What is the angle between the applied force and the resulting
acceleration of the proton?​

Answers

Answered by kalyanimukkala2
0

Answer:

proton with the rest mass of 1.67 x 10-24 kg is initially moving at 0.90c in the +x-direction,

relative to the reference frame of a physics laboratory

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