a) prove that log(99/35)=log11+2log3-log5-log7.
(or)
b) if p^2+q^2-7pq=0, show that 2 log(p+q/3)=log p+ log q.
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Step-by-step explanation:
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Answer:
a) taking LHS
=>log(99/35) {we know log(a/b)=log(a)-log(b)}
=>log(99) - log(35)
=>log(11*3*3) - log(5*7)
{we know log(a*b)=log(a) + log(b) }
=>log(11)+log(3)+log(3) - (log(5) +log(7))
=>log(11)+2*log(3)-log(5)-log(7) = RHS
Hence proved
b)
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