A pulley has a velocity ratio 5. If it pulls a load of 10kgf by 2m in 10s what is the power developed by it ?
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Answered by
1
power= work/ time
here work=mgh
mgh/t 10×10×2/10=20w
here work=mgh
mgh/t 10×10×2/10=20w
gillsaab2018:
or 2nd ans is by using both formule of energy as KE+PE/T=P
Answered by
0
Work done is 10 × 2 = 20 J
Power = Work / Time
= 20 J / 10 sec
= 2 watt
Power = Work / Time
= 20 J / 10 sec
= 2 watt
is 10N force is given
if it is then where
no 10 n force is not given
the other guy is wrong
you are totally correct
thank you very much
ur wlcm bro
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