A pulley system lifts a load of 600N by an effort of 200N .If the resistance due to movable parts of a machineis 400N.FInd
1.M.A.
2.V.R.
3.Number of pulley
4.Efficiency
Answers
Given info : A pulley system lifts a load of 600N by an effort of 200N.
To find : if the resistance due to movable parts of mechanics is 400N, find
- Machenical advantage
- velocity ratio
- number of pulleys
- efficiency
solution : machenical advantage = load/effort
= 600N/200N = 3
velocity ratio = number of pulleys = machenical advantage = 3
actual machenical advantage = MA - (resistance/load) = 3 - 400/200 = 3 - 2 = 1
so efficiency = actual MA/VR × 100
= 1/3 × 100
= 33 1/3 %
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